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Expand (1/x+y/3)^3 class 9-Algebra Expand using the Binomial Theorem (x3)^3 (x 3)3 ( x 3) 3 Use the binomial expansion theorem to find each term The binomial theorem states (ab)n = n ∑ k=0nCk⋅(an−kbk) ( a b) n = ∑ k = 0 n n C k ⋅ ( a n k b k) 3 ∑ k=0 3!ML Aggarwal Solutions for Class 9 Maths Chapter 3 – Expansions are provided here to help students prepare and excel in their exams This chapter mainly deals with problems based on expansions Experts tutors have formulated the solutions in a step by step manner for students to grasp the concepts easily From the exam point of view, solving




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We must use our knowledge of the binomial expansion Method 1 We can use (x 1)n = 1 nx n(n − 1) 2!1 Log in Join now 1 Log in Join now Ask your question Adrielle0423 Adrielle0423 1 week ago Mathematics High School 5 pts Answered Expand the following (x3)(x3) 2Expand (xy)^3 (x y)3 ( x y) 3 Use the Binomial Theorem x3 3x2y3xy2 y3 x 3 3 x 2 y 3 x y 2 y 3
x^33x^23x1 "note that" (xa)^3=x^3(aaa)x^2(aaaaaa)xa^3 (x1)^3toa=1 rArr(x1)^3=x^3(111)x^2(111)x(1)^3 =x^33x^23x1⋅(1)3−k ⋅(−x)k ∑ k = 0 3 3!Expand the following (i) `(4abac)^(2)` (ii) `(3a5bc)^(2)` (iii) `(x2y3z)^(2)` class9;



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⋅ (2x)2 3 ⋅ 2 ⋅ 1 3!⋅(x)3−k ⋅(3)k ∑ k = 0 3 Classify the following as linear, quadratic and cubic polynomials 1 x linear 143 Views Answer Classify the following as linear, quadratic and cubic polynomials x 2 x quadratic 118 Views Answer Classify the following as linear,




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⋅(2x)3−k ⋅(−y)k ∑ k = 0 3 y^33x^2y^23x^4yx^6 You can expand by using the identity (ab)^3=a^33a^2b3ab^2b^3 So, in this case, it is (yx^2)^3=y^33y^2(x^2)3y(x^2)^2(x^2)^3 =y^33x^2y^23x^4yx^6 Precalculus Science Anatomy & PhysiologyFind the Cube of the Following Binomials Expression 1 X Y 3 CBSE CBSE (English Medium) Class 9 Textbook Solutions 50 Important Solutions 1 Question Bank Solutions 7801 Concept Notes & Videos 2 Syllabus Advertisement Remove all ads Find the Cube of the Following




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Expand using the Binomial Theorem (2xy)^3 (2x − y)3 ( 2 x y) 3 Use the binomial expansion theorem to find each term The binomial theorem states (ab)n = n ∑ k=0nCk⋅(an−kbk) ( a b) n = ∑ k = 0 n n C k ⋅ ( a n k b k) 3 ∑ k=0 3!Get Instant Solutions, 24x7 No Signup Expand (1/xy/3)^3 solve it fastly density1 density1 Math Secondary School answered Expand (1/xy/3)^3 solve




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Click here👆to get an answer to your question ️ Expand the following (1 2x)^3 Expand the following 1/3(6/5x3) Get the answers you need, now! Explanation (x −y)3 = (x − y)(x −y)(x −y) Expand the first two brackets (x −y)(x − y) = x2 −xy −xy y2 ⇒ x2 y2 − 2xy Multiply the result by the last two brackets (x2 y2 −2xy)(x − y) = x3 − x2y xy2 − y3 −2x2y 2xy2 ⇒ x3 −y3 − 3x2y 3xy2 Always expand each term in the bracket by all the other




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